15x^2+23x+8=0

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Solution for 15x^2+23x+8=0 equation:



15x^2+23x+8=0
a = 15; b = 23; c = +8;
Δ = b2-4ac
Δ = 232-4·15·8
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*15}=\frac{-30}{30} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*15}=\frac{-16}{30} =-8/15 $

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